C++ 获取格式化时间戳的方法
获取时间戳是一个重要且常见的功能,通常在日志打印,请求响应过程中需要用到。通常精确到毫秒已经OK,一些情况下秒级也满足使用需求,这里记录一下自己开发过程获取时间戳的用法。
1.Linux系统函数 gettimeofday, 毫秒级时间戳
#include <sys/time.h>
//2021-10-06 13:13:09.935
static std::string getCurrentTime() {
struct timeval tv;
gettimeofday(&tv, NULL);
static const int MAX_BUFFER_SIZE = 128;
char timestamp_str[MAX_BUFFER_SIZE];
time_t sec = static_cast<time_t>(tv.tv_sec);
int ms = static_cast<int>(tv.tv_usec) / 1000;
struct tm tm_time;
localtime_r(&sec, &tm_time);
static const char *formater = "%4d-%02d-%02d %02d:%02d:%02d.%03d";
int wsize = snprintf(timestamp_str, MAX_BUFFER_SIZE, formater,
tm_time.tm_year + 1900, tm_time.tm_mon + 1, tm_time.tm_mday,
tm_time.tm_hour, tm_time.tm_min, tm_time.tm_sec, ms);
timestamp_str[min(wsize, MAX_BUFFER_SIZE - 1)] = '\0';
return std::string(timestamp_str);
2.使用标准库函数 chrono, 毫秒级时间戳
//2021-10-06 13:13:09.935
static std::string getCurrentTime() {
auto now = std::chrono::system_clock::now();
auto now_ms = std::chrono::duration_cast<std::chrono::milliseconds>(now.time_since_epoch());
auto sectime = std::chrono::duration_cast<std::chrono::seconds>(now_ms);
int32_t milltime = millitime.count() % 1000;
std::time_t timet = sectime.count();
struct tm curtime;
localtime_r(&timet, &curtime);
char buffer[64];
sprintf(buffer, "%4d-%02d-%02d %02d:%02d:%02d.%03d", curtime.tm_year + 1900, curtime.tm_mon + 1,
curtime.tm_mday, curtime.tm_hour, curtime.tm_min, curtime.tm_sec, milltime);
return std::string(buffer);
3.std::ctime, 秒级时间戳
//Wed Oct 6 13:13:09 2021
static std::string getCurrentTime0() {
std::time_t result = std::time(nullptr);
std::string ret;