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I am just started getting into classes and understand the basic concept however I don't understand why it gives me this error.
My code:
import pygame
pygame.init()
screen = pygame.display.set_mode((400, 300))
done = False
while not done:
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
class shape():
def __init__(self, place, colour, x, y):
self.place = place
self.colour = colour
self.x = x
self.y = y
class rectangle(shape):
def __init__(self, place, colour, x, y, length, width):
super().__init__(self, place, colour, x, y)
self.length = length
self.width = width
pygame.draw.rect(screen, colour, pygame.Rect(x, y, lenght, width))
Traceback (most recent call last):
File "Pygame.py", line 34, in <module>
Rectangle = rectangle(screen, (0, 128, 255), 30, 30, 60, 60)
File "Pygame.py", line 23, in __init__
super().__init__(self, place, colour, x, y)
TypeError: __init__() takes 5 positional arguments but 6 were given
I am not sure why it gives an error as I am creating a "rectangle" object. I found some examples and they seemed to be the same as mine.
–
The issue is in super().__init__(self, place, colour, x, y)
.
You are trying to call the initializer of a class you extends, but your rectangle
class is not extending any class, this means that the super()
is looking for something builtin class you don't have control over it.
Since you said you took this from an example, my guess is that you are missing to extend a class.
To make the script working you can remove the call to super().__init__...
I faced same issue , iam using python 2.7.x. I resolved it using classname directly. Here is the explination Python extending with - using super() Python 3 vs Python 2
Try this
shape.__init_(self,place, colour, x, y)
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