![]() |
苦恼的羊肉串 · 浙江省教育厅办公室关于组织参加第四届中华经典 ...· 1 年前 · |
![]() |
沉着的火车 · 佛山市发展和改革局关于佛山市编码佛南N72、 ...· 1 年前 · |
![]() |
温文尔雅的火龙果 · 极恶游戏 - 🌈️包子漫畫· 1 年前 · |
![]() |
不要命的茶叶 · 佩洛西今天去哪儿了,我们的军事反制有哪些选择 ...· 1 年前 · |
Give a try with the replace method on the output that you are receiving before processing it further.
Use this method -
String transformedText = ParserOutput.replace('""', '"');
Here ParserOutput is the string that contains the output to be transformed.
Thanks
All Answers
So your example would look like this:
"compannyName":"\"schiing\" Immobien & Co Lingasse KG"
PFB my JSON Output :
"mfr_part_number_mfrpn": ""PROMINENT,
BT5B0713P"
So my issue is if I have "Double Quotes" in my Out from DB then it is throwing me exceptions like
System.JSONException: Unexpected character ('P' (code 80)): was expecting comma to separate OBJECT entries at input location
Unexpected character ('<' (code 60)): expected a valid value (number, String, array, object, 'true', 'false' or 'null') at input location
System.JSONException: Unexpected character ('R' (code 82)): was expecting double-quote to start field name at input location
So bacically i want some workaround to delete off the Double quote in my Output and the above should become like :
"mfr_part_number_mfrpn": "PROMINENT,
BT5B0713P"
Give a try with the replace method on the output that you are receiving before processing it further.
Use this method -
String transformedText = ParserOutput.replace('""', '"');
Here ParserOutput is the string that contains the output to be transformed.
Thanks
Awesome my issue got solved...!