@Test
    public void test() {
        // 提取张三 去除数字
        String r_name3 = "张三 13599998888 000000";
        Pattern pattern = Pattern.compile("[\\d]");
        Matcher matcher = pattern.matcher(r_name3);
        System.out.println(matcher.replaceAll("").trim());
需求：过滤除点号外的所有非数字:
        String abc = "价格：0.00元";
        Pattern compile = Pattern.compile("\\d+\\.\\d+");
        Matcher matcher = compile.matcher(abc);
        matcher.find();
        String string = matcher.group();//提取匹配到的结果
        System.out.println(string);//0.00        
需求：只要提取数字其它都不需要
String abc = "手机：1319999999";    
System.out.println(abc.replaceAll("\\D", ""));//1319999999
 需求：提取价格出来
package com.infomorrow.parser_datasource;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import org.junit.Test;
public class test_money {
    @Test
    public void test(){
        //0.1
        //24.13
        String moneyString="1";
        Double extract_cost = extract_cost_dot(moneyString);
        System.out.println("extract_cost:"+extract_cost);
     * 提取金额,规则为只提取数字和点号,必须有点号
     * 格式可以为0.0或者，11
     * @param cost
     * @return
    public   Double extract_cost_dot(String cost) {
        Pattern compile = Pattern.compile("(\\d+\\.\\d+)|(\\d+)");
        Matcher matcher = compile.matcher(cost);
        matcher.find();
        return Double.valueOf(matcher.group());