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there is a check button on windows use python win32gui.i can find the handle and check it using PostMessage. here is code

    bt=win32gui.FindWindowEx(hwnd,None,'Button','设置用户信息(&L)')
    win32gui.PostMessage(bt,win32con.WM_KEYDOWN, win32con.VK_SPACE, 0)
    win32gui.PostMessage(bt,win32con.WM_KEYUP, win32con.VK_SPACE, 0)
but if I accidentally run the program twice, the check button's state will be recovered
Is there any way to Judge before check,if it is checked ,the program  will do nothing.
a check button on windows
i try to find the api of the win32gui ,but Nothing found
                Use UI Automation to automate your UI. That's the technology that underpins pywinauto's uia backend.
– IInspectable
                Sep 11 at 12:37
                thank you for reply,I found the solution SendMessage(handleToControl, BM_GETCHECK, 0, 0);
– 张星星
                Sep 13 at 9:47
                UI Automation is a formal way. Now that you found the workaround, would you answer yourself?
– YangXiaoPo-MSFT
                Sep 14 at 1:11
                That's not a solution. It just gets you one step closer to repeating the same mistake all over again: You can't simulate keyboard input with PostMessage. That's the issue that needs to be solved, and UI Automation is the solution.
– IInspectable
                Sep 14 at 8:39
        
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