项目中可能需要用到Dictionary 排序,于是先做了一个小demo ,网上搜索真的没有能满足我需要的,都是类似的,于是理解改造,一上午就在查找,实践中过去了。现在把它实现了,把代码贴出来,算是一个笔记吧。希望给需要的人也一个参考。
一、C# 版本
public void gettest()
Dictionary<string, string> dic1 = new Dictionary<string, string>();
dic1.Add("2015-4-01", "2015-4-05");
dic1.Add("2015-4-29", "2015-5-01");
dic1.Add("2015-4-07a", "2015-4-10");
dic1.Add("2015-4-07b", "2015-4-10");
dic1.Add("2015-5-02", "2015-5-08");
dic1.Add("2015-4-11", "2015-4-20");
dic1.Add("2015-4-21", "2015-4-28");
Dictionary<string, string> dic1Asc = dic1.OrderBy(o => o.Key).ToDictionary(o => o.Key, p => p.Value);
Dictionary<string, string> dic1desc = dic1.OrderByDescending(o => o.Key).ToDictionary(o => o.Key, p => p.Value);
Dictionary<string, string> dic1Asc1 = (from d in dic1 orderby d.Key ascending select d).ToDictionary(k => k.Key, v => v.Value);
Dictionary<string, string> dic1desc2 = (from d in dic1 orderby d.Key descending select d).ToDictionary(k => k.Key, v => v.Value);
foreach (KeyValuePair<string, string> kvp in dic1Asc)
Response.Write(string.Format("开始日期 = {0}, 结束日期 = {1} <br/>", kvp.Key, kvp.Value));
public void gettest2()
Dictionary<string, string> dic1 = new Dictionary<string, string>();
dic1.Add("2015-4-01", "2015-4-05");
dic1.Add("2015-4-29", "2015-5-01");
dic1.Add("2015-4-07a", "2015-4-10");
dic1.Add("2015-4-07b", "2015-4-10");
dic1.Add("2015-5-02", "2015-5-08");
dic1.Add("2015-4-11", "2015-4-20");
dic1.Add("2015-4-21", "2015-4-28");
Response.Write("<br />正序排序数据:<br />");
foreach (KeyValuePair<string, string> item in dic1)
Response.Write("键名:" + item.Key + " 键值:" + item.Value + "<br />");
Dictionary<string, string> dc = new Dictionary<string, string>();
foreach (KeyValuePair<string, string> kvp in dic1.Reverse())
dc.Add(kvp.Key, kvp.Value);
dic1 = null;
//再看其输出结果:
Response.Write("<br />反序排序数据:<br />");
foreach (KeyValuePair<string, string> item in dc)
Response.Write("键名:" + item.Key + " 键值:" + item.Value + "<br />");
public void gettest3()
Dictionary<string, string> dic1 = new Dictionary<string, string>();
dic1.Add("2015-4-01", "2015-4-05");
dic1.Add("2015-4-29", "2015-5-01");
dic1.Add("2015-4-07a", "2015-4-10");
dic1.Add("2015-4-07b", "2015-4-10");
dic1.Add("2015-5-02", "2015-5-08");
dic1.Add("2015-4-11", "2015-4-20");
dic1.Add("2015-4-21", "2015-4-28");
List<KeyValuePair<string, string>> myList = new List<KeyValuePair<string, string>>(dic1);
myList.Sort(delegate(KeyValuePair<string, string> s1, KeyValuePair<string, string> s2)
return s1.Value.CompareTo(s2.Value);
dic1.Clear();
foreach (KeyValuePair<string, string> pair in myList)
dic1.Add(pair.Key, pair.Value);
foreach (string key in dic1.Keys)
Response.Write(string.Format("开始日期:{0}<br/>",dic1[key]));
二、vb.net版本
Public Sub gettest()
Dim dic1 As Dictionary(Of String, String) = New Dictionary(Of String, String)
dic1.Add("2015-4-01", "2015-4-05")
dic1.Add("2015-4-29", "2015-5-01")
dic1.Add("2015-4-07a", "2015-4-10")
dic1.Add("2015-4-07b", "2015-4-10")
dic1.Add("2015-5-02", "2015-5-08")
dic1.Add("2015-4-11", "2015-4-20")
dic1.Add("2015-4-21", "2015-4-28")
Dim myList As List(Of KeyValuePair(Of String, String)) = sortByValue(dic1)
For Each kvp As KeyValuePair(Of String, String) In myList
'Console.WriteLine(kvp.Key & ":" & kvp.Value)
Response.Write(String.Format("开始日期:{0}<br/>", kvp.Key))
End Sub
Public Sub gettest2()
Dim dic1 As Dictionary(Of String, String) = New Dictionary(Of String, String)
dic1.Add("2015-4-01", "2015-4-05")
dic1.Add("2015-4-29", "2015-5-01")
dic1.Add("2015-4-07a", "2015-4-10")
dic1.Add("2015-4-07b", "2015-4-10")
dic1.Add("2015-5-02", "2015-5-08")
dic1.Add("2015-4-11", "2015-4-20")
dic1.Add("2015-4-21", "2015-4-28")
Dim myList As List(Of KeyValuePair(Of String, String)) = New List(Of KeyValuePair(Of String, String))(dic1)
myList.Sort(Function(s1 As KeyValuePair(Of String, String), s2 As KeyValuePair(Of String, String))
Return s1.Value.CompareTo(s2.Value)
End Function)
For Each kvp As KeyValuePair(Of String, String) In myList
'Console.WriteLine(kvp.Key & ":" & kvp.Value)
Response.Write(String.Format("开始日期:{0}<br/>2<br/>", kvp.Key))
End Sub
Shared Function hikaku(ByVal kvp1 As KeyValuePair(Of String, String), ByVal kvp2 As KeyValuePair(Of String, String)) As String
Return kvp1.Value.CompareTo(kvp2.Value)
' Return kvp2.Value - kvp1.Value
End Function
Shared Function sortByValue(ByVal dict As Dictionary(Of String, String)) As List(Of KeyValuePair(Of String, String))
Dim list As New List(Of KeyValuePair(Of String, String))(dict)
list.Sort(AddressOf hikaku)
Return list
End Function
C#的理解好一些,vb.net的有点难度,花了不少时间。
参考 :http://www.cnblogs.com/sekihin/archive/2008/08/27/1277605.html