如何在Python中启动后台进程？

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如何在Python中启动后台进程？

import os
os.system("some_command &")

import os
os.spawnl(os.P_DETACH, 'some_long_running_command')

try:
    pid = os.fork()
except OSError, e:
    ## some debug output
    sys.exit(1)
if pid == 0:
    ## eventually use os.putenv(..) to set environment variables
    ## os.execv strips of args[0] for the arguments
    os.execv(args[0], args)

import subprocess
subprocess.Popen(["rm","-r","some.file"])

import subprocess
ls_output=subprocess.Popen(["sleep", "30"])
ls_output.communicate()  # Will block for 30 seconds

DETACHED_PROCESS = 0x00000008
pid = subprocess.Popen([sys.executable, "longtask.py"],
                       creationflags=DETACHED_PROCESS).pid

import os, time, sys, subprocess
if len(sys.argv) == 2:
    time.sleep(5)
    print 'track end'
    if sys.platform == 'darwin':
        subprocess.Popen(['say', 'hello'])
else:
    print 'main begin'
    subprocess.Popen(['python', os.path.realpath(__file__), '0'], close_fds=True)
    print 'main end'

#!/usr/bin/env python3
import os
import subprocess
import sys
import threading
def output_reader(proc, file):
    while True:
        byte = proc.stdout.read(1)
        if byte:
            sys.stdout.buffer.write(byte)
            sys.stdout.flush()
            file.buffer.write(byte)
        else:
            break
with subprocess.Popen(['./sleep.py', '0'], stdout=subprocess.PIPE, stderr=subprocess.PIPE) as proc1, \
     subprocess.Popen(['./sleep.py', '10'], stdout=subprocess.PIPE, stderr=subprocess.PIPE) as proc2, \
     open('log1.log', 'w') as file1, \
     open('log2.log', 'w') as file2:
    t1 = threading.Thread(target=output_reader, args=(proc1, file1))
    t2 = threading.Thread(target=output_reader, args=(proc2, file2))
    t1.start()
    t2.start()
    t1.join()
    t2.join()

#!/usr/bin/env python3
import sys
import time
for i in range(4):
    print(i + int(sys.argv[1]))
    sys.stdout.flush()
    time.sleep(0.5)

./main.py

如何在Python中启动后台进程？

9 个回答