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Learn more about Teams For those saying "it works for me", the behavior of echo varies quite a bit between versions. Some will even print the "-e" as part of their output. If you want predictable behavior for anything nontrivial, use printf instead (as in @sth's answer). Gordon Davisson Dec 12, 2011 at 1:58 I could not get any of the suggestions in this answer working, because, as it turns out, I was attempting to use it in a function that returns a value , and all the echo (and printf) messages in the function were being appended to the return value after being individually stripped of newlines . Here is a question regarding this, with an extremely thorough answer: stackoverflow.com/questions/27872069/… This was like a three hour mystery tour. aliteralmind Jan 10, 2015 at 3:28 Also notable: in Unix & Linux Stack Exchange, the accepted answer to How to add new lines when using echo Graham Perrin Apr 9, 2016 at 7:02 echo -ne "hello\nworld" (you needed the n flag to interpret escapes) - but as others say, different echo commands may have different results! Konchog Mar 28, 2018 at 7:00 @Konchog echo -n man page entry on archlinux ` -n do not output the trailing newline` It has nothing to do with interpreting escapes user12207064 May 27, 2020 at 18:19 or even printf %"s\n" hello world -- printf will reuse the format if too many arguments are given glenn jackman Dec 12, 2011 at 0:57 The OP asked about echo, not printf; and @choroba's answer below, which uses the -e option, fills the bill perfectly. JESii May 27, 2015 at 13:46 With some versions of echo , -e is just printed in the output itself so I think this answer is perfectly valid since echo isn't consistent here (unless we're talking about a specific version). Tejas Manohar Jun 10, 2015 at 19:47 This is well and good if printf is available, but unlike echo sometimes printf isn't on the distro. bigtunacan Aug 18, 2015 at 13:53 As mentioned by various other -e does NOT work for all distributions and versions. In some cases it is ignored and in others it will actually be printed out. I don't believe this fixed it for the OP so should not be accepted answer csga5000 Apr 15, 2016 at 4:23 @EvgeniSergeev Not sure what you mean, but it didn't work for me either first. And that's because I was using double quotes and turns out this works only with single quotes! Tried in Terminal on Mac. trss Oct 1, 2016 at 5:49 For me this is the only right answer to the asked question. It does not use another command and relies on bash. An extra echo does the wrong job here. One point I want to add: It seems to only work on bourne-like shells, which is basically every shell used out there... ( see here ) void Feb 8, 2022 at 10:18 echo "" works for me and I think it's the simplest form to print a new line, even if this doesn't directly answer the question. Cheers. Mario Awad Mar 24, 2014 at 20:00 The \n did not work when you are using the read . But your method worked for adding a line. Codename K Oct 12, 2020 at 19:11 i had trouble getting the other answers to work on Mac. i ended up going with this incredibly obvious solution. :) Kip Oct 22, 2021 at 12:12

On the off chance that someone finds themselves beating their head against the wall trying to figure out why a coworker's script won't print newlines, look out for this:

#!/bin/bash
function GET_RECORDS()
   echo -e "starting\n the process";
echo $(GET_RECORDS);

As in the above, the actual running of the method may itself be wrapped in an echo which supersedes any echos that may be in the method itself. Obviously, I watered this down for brevity. It was not so easy to spot!

You can then inform your comrades that a better way to execute functions would be like so:

#!/bin/bash
function GET_RECORDS()
   echo -e "starting\n the process";
GET_RECORDS;
                Vastly underrated answer, can't believe this question has amassed 20+ answers since 2011 and that not one of them contains this simple solution.
– Hashim Aziz
                Dec 4, 2019 at 17:37
                alias c='echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ; echo ;'  This is the only way I can clear my screen, thanks!
– Ahi Tuna
                Dec 9, 2019 at 14:38

http://pubs.opengroup.org/onlinepubs/9699919799/utilities/echo.html

-e is not defined and backslashes are implementation defined:

If the first operand is -n, or if any of the operands contain a <backslash> character, the results are implementation-defined.

unless you have an optional XSI extension.

So I recommend that you should use printf instead, which is well specified:

format operand shall be used as the format string described in XBD File Format Notation [...]

the File Format Notation:

\n <newline> Move the printing position to the start of the next line.

Also keep in mind that Ubuntu 15.10 and most distros implement echo both as:

  • a Bash built-in: help echo
  • a standalone executable: which echo
  • which can lead to some confusion.

    For only the question asked (not special characters etc) changing only double quotes to single quotes.

    echo -e 'Hello,\nWorld!'
    

    Results in:

    Hello,
    World!
                    Why bother to invoke a second program? It's not that we are trying to write a real time application in bash ;) but its not necessary.
    – Felix D.
                    Aug 4, 2017 at 8:16
    

    This works both inside a script and from the command line.

    On the command line, press Shift+Enter to do the line break inside the string.

    This works for me on my macOS and my Ubuntu 18.04 (Bionic Beaver) system.

    There is a new parameter expansion added in Bash 4.4 that interprets escape sequences:

    ${parameter@operator} - E operator

    The expansion is a string that is the value of parameter with backslash escape sequences expanded as with the $'…' quoting mechanism.

    $ foo='hello\nworld'
    $ echo "${foo@E}"
    hello
    world
                    worked like a charm for printing a message that was a variable inside a function, from outside the function.
    – Shōgun8
                    Nov 22, 2021 at 15:33
    

    -e option will interpret backslahes for the escape sequence
    -n option will remove the trailing newline in the output

    PS: the command echo has an effect of always including a trailing newline in the output so -n is required to turn that thing off (and make it less confusing)

    Output:

    WARNING : 2 WARNINGS FOUND:\nWarning, found the following local orphaned signature file:
    

    On my Bash script I was getting mad as you until I've just tried:

    echo "WARNING : $warningsFound WARNINGS FOUND:
    $warningStrings"
    

    Just hit Enter where you want to insert that jump. The output now is:

    WARNING : 2 WARNINGS FOUND:
    Warning, found the following local orphaned signature file:
                    Just a note, you will probably want to use ${ } around your variable names as not doing so can lead to really weird behavior when  a shell finds a variable called $warningsFound and prints that and not the two separate outputs.
    – dragon788
                    Jan 27, 2016 at 21:06
                    @dragon788 maybe I'm missing something, but the variable IS actually called $warningsFound ?
    – psx
                    Feb 10, 2017 at 9:47
                    I missed a word on that. If you had a variable called $warnings, in some cases without using ${warningsFound}, you could potentially end up with the contents of $warnings + "Found" instead of the variable you intended.
    – dragon788
                    Feb 10, 2017 at 13:12
    

    If you're writing scripts and will be echoing newlines as part of other messages several times, a nice cross-platform solution is to put a literal newline in a variable like so:

    newline='
    echo "first line${newline}second line"
    echo "Error: example error message n${newline}${usage}" >&2 #requires usage to be defined
    

    If the previous answers don't work, and there is a need to get a return value from their function:

    function foo()
        local v="Dimi";
        local s="";
        .....
        s+="Some message here $v $1\n"
        .....
        echo $s
    r=$(foo "my message");
    echo -e $r;
    

    Only this trick worked on a Linux system I was working on with this Bash version:

    GNU bash, version 2.2.25(1)-release (x86_64-redhat-linux-gnu)
    

    This got me there....

    outstuff=RESOURCE_GROUP=[$RESOURCE_GROUP]\\nAKS_CLUSTER_NAME=[$AKS_CLUSTER_NAME]\\nREGION_NAME=[$REGION_NAME]\\nVERSION=[$VERSION]\\nSUBNET-ID=[$SUBNET_ID]
    printf $outstuff
    

    Yields:

    RESOURCE_GROUP=[akswork-rg]
    AKS_CLUSTER_NAME=[aksworkshop-804]
    REGION_NAME=[eastus]
    VERSION=[1.16.7]
    SUBNET-ID=[/subscriptions/{subidhere}/resourceGroups/makeakswork-rg/providers/Microsoft.Network/virtualNetworks/aks-vnet/subnets/aks-subnet]
                    An explanation would be in order. E.g, what is the gist/idea? Please respond by editing your answer, not here in comments (without "Edit:", "Update:", or similar - the answer should appear as if it was written today).
    – Peter Mortensen
                    Jul 9, 2021 at 17:01
    

    Sometimes you can pass multiple strings separated by a space and it will be interpreted as \n.

    For example when using a shell script for multi-line notifcations:

    #!/bin/bash
    notify-send 'notification success' 'another line' 'time now '`date +"%s"`
                    This is incorrect. It is never interpreted as \n. It is interpreted as a separate argument to the program, and the program itself may display that argument on a new line, but that doesn't mean that it was converted to \n at any point and is entirely dependent on the program.
    – Score_Under
                    Mar 27, 2019 at 10:52
    

    Additional solution:

    In cases, you have to echo a multiline of the long contents (such as code/ configurations)

    For example:

  • A Bash script to generate codes/ configurations
  • echo -e, printf might have some limitation

    You can use some special char as a placeholder as a line break (such as ~) and replace it after the file was created using tr:

    echo ${content} | tr '~' '\n' > $targetFile
    

    It needs to invoke another program (tr) which should be fine, IMO.

    This is a poor solution. There is absolutely no need to invoke tr in this case. Furthermore, what if the text includes a ~ already? – blackbrandt Jul 22, 2020 at 15:14