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Python 3

d.items() returns the iterator; to get a list, you need to pass the iterator to list() yourself.

for k, v in d.items():
    print(k, v)
Python 2
You can get an iterator that contains both keys and values. d.items() returns a list of (key, value) tuples, while d.iteritems() returns an iterator that provides the same:
for k, v in d.iteritems():
    print k, v
A little intro to dictionary
d={'a':'apple','b':'ball'}
d.keys()  # displays all keys in list
['a','b']
d.values() # displays your values in list
['apple','ball']
d.items() # displays your pair tuple of key and value
[('a','apple'),('b','ball')
Print keys,values method one
for x in d.keys():
    print(x +" => " + d[x])
Another method
for key,value in d.items():
    print(key + " => " + value)
You can get keys using iter
>>> list(iter(d))
['a', 'b']
You can get value of key of dictionary using get(key, [value]):
d.get('a')
'apple'
If key is not present in dictionary,when default value given, will return value.
d.get('c', 'Cat')
'Cat'
                i think this should definitely be a more accepted answer! ... i feel this answer demos the type of power in python that is mostly ignored... you can also do the follow to get rid of the '()' ... print(*[f"{': '.join(map(str,v))}" for i,v in enumerate(list(d.items()))], sep='\n') .... or you can do the following to conveniently print index #'s as well print(*[f"[{i}] {': '.join(map(str,v))}" for i,v in enumerate(list(d.items()))], sep='\n')
– greenhouse
                Jul 16, 2019 at 11:03
                Can somebody explain why the * is needed and how it converts dict_values to actual values. Thank you.
– MichaelE
                Jan 20, 2021 at 22:28
                The * operator also works as an "unpacker" (besides multiplying). So what happens is that it unpacks the dictionary items. It doesn't convert, I would say it "opens" the box that d.items() is, and print receives the contents. "unpacking operator python" is the keyword for a more technical explanation.
– Nara Begnini
                Jan 22, 2021 at 1:04
                not sure why you think this might be not a good practice, while i think a request to access to I/O with print command per each key-pair is much worse practice from efficiency point of view
– Leon Proskurov
                Apr 18 at 11:42
You can access your keys and/or values by calling items() on your dictionary.
for key, value in d.iteritems():
    print(key, value)
                you said items() in the first line of your text and in the code you put iteritems(). In python3x the correct way is the dict.items() as you said first.
– Joel Carneiro
                Dec 21, 2018 at 10:18
                I actually tried to use d.iteritems(): first and got AttributeError: 'dict' object has no attribute 'iteritems'. I was using Python 3 and switched ti d.items() and it worked, because iteritems seems to have been removed from Python 3.   You can read about the difference between Python 2 and 3 in this thread: stackoverflow.com/questions/30418481/…
– AwfulPersimmon
                Apr 4 at 19:29
If you want to sort the output by dict key you can use the collection package.
import collections
for k, v in collections.OrderedDict(sorted(d.items())).items():
    print(k, v)
It works on python 3
In addition to ways already mentioned..  can use 'viewitems', 'viewkeys', 'viewvalues'
>>> d = {320: 1, 321: 0, 322: 3}
>>> list(d.viewitems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.viewkeys())
[320, 321, 322]
>>> list(d.viewvalues())
[1, 0, 3]
>>> list(d.iteritems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.iterkeys())
[320, 321, 322]
>>> list(d.itervalues())
[1, 0, 3]
or using itemgetter
>>> from operator import itemgetter
>>> map(itemgetter(0), dd.items())     ####  for keys
['323', '332']
>>> map(itemgetter(1), dd.items())     ####  for values
['3323', 232]
                It appears these methods have been deprecated in later releases of Python 3. 3.10 does not have those methods.
– Nathan
                Feb 28, 2022 at 21:46
To print a specific (key, value) pair in Python 3 (pair at index 1 in this example):
for e in range(len(x)):
    print(([x for x in x.keys()][e], [x for x in x.values()][e]))
Output:
('X', 'yes')
('Y', 'no')
('Z', 'ok')
Here is a one liner solution to print all pairs in a tuple:
print(tuple(([x for x in x.keys()][i], [x for x in x.values()][i]) for i in range(len(x))))
Output:
(('X', 'yes'), ('Y', 'no'), ('Z', 'ok'))
 'lebron': 'lakers', - Lebron is key and lakers is value
for loop - specify key, value in dictionary.item():
Now Print (Player Name is the leader of club).
the Output is:
#Lebron is the leader of lakers
#Giannis is the leader of milwakee bucks
#Durant is the leader of brooklyn nets
#Kawhi is the leader of clippers
If you're looking for pretty-printing a dictionary, check out Rich:
from rich import print
prices = {
    "banana": 4,
    "apple": 2,
    "orange": 1.5,
    "pear": 3,
    "strawberry": 1,
    "blueberry": 0.5,
    "mango": 4.5
print(prices)